CBSE Class 12 Physics 2019 Outside Delhi Set 1 Paper

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Question : 18
Total: 27
A signal of low frequency fm is to be transmitted using a carrier wave of frequency fc. Derive the expression for the amplitude modulated wave and deduce expressions for the lower and upper sidebands produced. Hence, obtain the expression for modulation index.
Solution:  
Derive expression for amplitude modulated wave.
Deducing expression for lower and upper side bands.
Obtaining expression for modulation index.
Let a carrier wave be given by
c(t)=Acsin‌ωct where ωc=2πfc
And signal wave be
m(t)sin‌ωmt where ωm=2πfm
The modulated signal is
cm(t)=(Ac+Amsin‌ωmt)sin‌ωct
cm(t)=Ac(1+‌
Am
Ac
s
i
n
‌ωmt
)
s
i
n
‌ωct

cm(t)=Acsin‌ωct+µ‌
Ac
2
‌cos
(ωc−ωm)
‌t
‌‌−µ‌
Ac
2
‌cos
(ωc+ωm)
‌t

The modulation index µ=‌
Am
Ac

Lower frequency band ωc−ωm
Upper frequency band ωc+ωm
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