Test Index

CBSE Class 12 Physics 2019 Delhi Set 3 Paper

© examsnet.com
Question : 4
Total: 8
A charged particle q is moving in the presence of a magnetic field B which is inclined to an angle 30∘ with the direction of motion of the particle. Draw the trajectory followed by the particle in the presence of the field and explain how the particle describes this path.
Solution:  

Since magnetic force is given as,
‌
→
F
‌=q(
→
v
×
→
B
)
‌ or ‌‌F‌=qvBsin‌θ
‌ here, ‌‌θ‌=30∘
‌F‌=‌
qvB
2
Velocity component parallel to the field moves particle in straight line and velocity component perpendicular to the field creates circular motion thus the combined effect is the helical path.
© examsnet.com
Go to Question:
Prev Question
Next Question