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CBSE Class 12 Physics 2019 Delhi Set 2 Paper

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Question : 5 of 6
Marks: +1, -0
(a) Draw equipotential surfaces corresponding to the electric field that uniformly increases in magnitude along with the Z-direction.
(b) Two charges q and +q are located at point (0,0,a) and (0,0,a). What is the electrostatic potential at the points (0,0,±z) and (x,y,0) ?
Solution:  
(a)

Vz=kq(za)+k(q)(z+a) if z>a
=Kq[1za1z+a]=Kq2az2a2
Potential at pt. (0,0z)
V(z)=Kq(za)+K(q)(z+a)
=Kq[1za1z+a]
=Kq2az2a2
r for the point is x2+y2+a2
V(x,y,0)=Kq(x2+y2+a2)12 +K(q)(x2+y2+a2)12
=0.
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