CBSE Class 12 Physics 2019 Delhi Set 1 Paper

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Question : 21
Total: 27
Define the term 'decay constant' of a radioactive sample. The rate of disintegration of a given radioactive nucleus is 10000 disintegrations/s and 5000 disintegrations/s after 20hr and 30hr. respectively from start. Calculate the half life and initial number of nuclei at t=0
Solution:  
Definition of decay constant
Calculation of half life
Calculation of initial number of nuclei at t=0
The decay constant (λ) of a radioactive nucleus equals the ratio of the instantaneous rate of decay (
N
t
)
to the corresponding instantaneous number of radioactive nuclei.
Alternatively,
The decay constant (λ) of a radioactive nucleus is the constant of proportionality in the relation between its rate of decay and number of its nuclei at any given instant.
Alternatively,
(
N
t
)
N

(
N
t
)
=λN

The constant (λ) is known as the decay constant
Alternatively,
The decay constant equals the reciprocal of the mean life of a given radioactive nucleus.
λ=
1
τ

where, τ= mean life
Alternatively,
The decay constant equal the ratio of ln2 to the half life of the given radioactive element.
λ=
ln2
T12

where T12= Half life
Alternatively,
The decay constant of a radioactive element, is the reciprocal of the time in which the number of its nuclei reduces to
1
e
of its original number.
We have
R=λN
R(20hrs)=10000=λN20
R(30hrs)=5000=λN30
N20
N30
=2

This means that the number of nuclei, of the given radioactive nucleus, gets halved in a time of (3020) hours =10 hours
Half life =10 hours
This means that in 20 hours ( =2 half lives), the original number of nuclei must have gone down by a factor of 4 .
Hence Rate of decay at t=0
λN0=4λN20
=4×10000=40,000 disintegrations per second
[Note : Award full marks of the last part of this question even if student does not calculate initial number of nuclei and calculates correctly rate of disintegration at t=0 ]
i.e., R0=40,000 disintegrations per second
N0=
40000
λ
=
40000
ln2
×10×60×60
N0=
144×107
0.693
=2.08×109 nuclei
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