CBSE Class 12 Physics 2017 Outside Delhi Set 1 Paper

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Question : 8
Total: 26
Find the condition under which the charged particles moving with different speeds in the presence of electric and magnetic field vectors can be used to select charged particles of a particular speed.
Solution:  
Condition
(i)For directions of E,B,
→
v

(ii)For magnitudes of
→
E
,
→
B
,
→
v

(i)The velocity
→
v
, of the charged particles, and the
→
E
and
→
B
vectors, should be mutually perpendicular.
Also the forces on q , due to
→
E
and
→
B
, must be oppositely directed.
(Also accept if the student draws a diagram to show the directions.)

(ii) qE=qvB
‌ or ‌v=‌
E
B

[Alternatively, The student may write : Force due to electric field =q
→
E

Force due to magnetic field =q(
→
v
×
→
B
)

The required condition is
q
→
E
‌
=−q(
→
v
×
→
B
)

‌ [or ‌
→
E
‌
=−(
→
v
×
→
B
)
=(
→
B
×
→
v
)
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