CBSE Class 12 Physics 2016 Delhi Set 1 Paper

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Question : 16
Total: 26
Two long straight parallel conductors carry steady current I1 and I2 separated by a distance d. If the currents are flowing in the same direction, show how the magnetic field set up in one produces an attractive force on the other. Obtain the expression for this force. Hence define one ampere.
Solution:  
Diagram showing attractive force on other wire.

Obtaining an expression for force.

Definition of one ampere.

As shown in Figure, the direction of force on conductor b is attractive
[Alternatively:
→
B
at a point on wire 2 , is along −
^
k

∴
→
F
, on wire 2 , due to the
→
B
, is along −
^
i
, i.e. towards wire1. Hence the force is attractive.

Magnetic field, due to current in conductor a ,
B1=‌
µ0I1
2Ï€d

The magnitude of force on a length L of conductor b ,
‌F2=I2LB1
‌F2=‌
µ0I1I2L
2Ï€d

One ampere is that steady current which, when maintained in each of the two very long, straight, parallel conductors, placed one meter apart in vacuum, would produce on each of these conductors a force equal to 2×10−7 newton per meter of theirlength.
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