CBSE Class 12 Physics 2014 Delhi Set 3 Paper

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Question : 4
Total: 8
An electric dipole of length 2‌cm , when placed with its axis making an angle of 60∘ with a uniform electric field, experiences torque of 6√3‌Nm . Calculate the potential energy of the dipole, if it has a charge of ±2nC .
Solution:  
τ‌=pEsin‌θ
6√3‌=pEsin‌θ
pE‌
√3
2
‌
=6√3

So, pE=12
Potential energy of the dipole =−pE‌cos‌θ
‌U=−pE‌cos‌60∘
‌U=−12×0.5
‌U=−6J
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