CBSE Class 12 Physics 2014 Delhi Set 1 Paper

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Question : 22
Total: 30
(i) Draw a labelled ray diagram showing the formation of a final image by a compound microscope at least distance of distinct vision.
(ii) The total magnification produced by a compound microscope is 20 . The magnification produced by the eye piece is 5 . The microscope is focussed on a certain object. The distance between the objective and eye-piece is observed to be 14‌cm. If least distance of distinct vision is 20‌cm, calculate the focal length of the objective and the eye piece.
Solution:  
(i)

(ii) From m‌=m0×me
m0‌=‌
m
me
=‌
20
5
=4

Now, m0‌=‌
v0
u0
=‌
L
f0
=4

f0‌=‌
L
4
=‌
14
4
=3.5‌cm

Also, me‌=1+‌
d
fe
=5

‌
d
fe
‌
=5−1
=4

fe‌=‌
d
4
=‌
20
4
=5‌cm
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