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CBSE Class 12 Math 2026 All Sets Solved Paper

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Question : 7 of 20
Marks: +1, -0
The least value of f(x)=x3−12x,x∈[0,3]f(x)=x^{3}-12x, x\in[0,3] is
Solution:  
f(x)=x3−12x,x∈[0,3]f(x)=x^{3}-12x, x\in[0,3]
f′(x)=3x2−12=0f'(x)=3x^{2}-12=0
⇒x2=  123⇒x=±2\Rightarrow x^{2}=\;\frac{12}{3} \Rightarrow x=\pm 2
f(0)=0,f(3)=−9,f(2)=−16f(0)=0, f(3)=-9, f(2)=-16
Least value of f(x) is -16 at x = 2.
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