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Question : 4
Total: 14
The value of
( s i n 2 x ) dx
Solution:
Explanation:
s i n 2 x dx
Letu = 2 x
Ifx = 0 u = 0
and x = π ∕ 4 then u = π ∕ 2 .
⇒ d u = 2 dx
sin u du = −
[ cos u ] 0 π ∕ 2
= −
[ 0 − 1 ] =
Let
If
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