\sin [\frac{\pi}{3}+ \sin ^{-1} (\frac{1}{2}) ] is equal to:

CBSE Class 12 Math 2023 Delhi Set 1 Solved Paper

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Question : 2 of 38

Marks: +1, -0

sin‌[‌

π

3

+sin‌−1(‌

1

2

)] is equal to:

1
‌
1
2
‌
1
3
‌
1
4

Solution: 👈: Video Solution

‌ Explanation: ‌sin‌[‌

π

3

+sin‌−1(‌

1

2

)]
‌‌‌‌sin‌(‌

π

3

+‌

π

6

)=sin‌‌

π

2

=1

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