CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 8
Total: 50
If (x2+y2)2=xy, then ‌
dy
dx
is
Explanation: Given, (x2+y2)2=xy
⇒‌‌x4+2x2y2+y4−xy=0
Differentiating w.r.t. x, we get
4x3+2[2xy2+x2⋅2y‌
dy
dx
]
+4y3‌
dy
dx
−[y+x‌
dy
dx
]
=0

‌
dy
dx
[4x2y+4y3−x]
+[4x3+4xy2−y]
=0

‌
dy
dx
=‌
−[4x3+4xy2−y]
[4x2y+4y3−x]

‌ or ‌‌‌‌
dy
dx
=‌
y−4x(x2+y2)
4y(x2+y2)−x

‌
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