CBSE Class 12 Math 2022 Term I Solved Paper

Question : 4

Total: 50

If sin‌y=x‌cos(a+y), then ‌

Solution: 👈: Video Solution

Explanation: Given, sin‌y=x‌cos(a+y)
⇒‌‌x=‌

sin‌y

cos(a+y)

Differentiating with respect to y, we get
‌

‌=‌

cos(a+y)‌

(sin‌y)−sin‌y

{cos(a+y)}

cos2(a+y)

⇒‌

‌=‌

cos(a+y)‌cos‌y−sin‌y[−sin‌(a+y)]

cos2(a+y)

⇒‌

‌=‌

cos(a+y)‌cos‌y+sin‌ysin‌(a+y)

cos2(a+y)

⇒‌

‌=‌

cos[(a+y)−y]

cos2(a+y)

⇒‌

‌=‌

cos2a

cos2(a+y)

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