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CBSE Class 12 Math 2022 Term I Solved Paper

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Question : 18 of 50
Marks: +1, -0
[3c+6a−da+d2−3b]=[122−8−4] are equal, then value of ab−cd is
Solution:     👈: Video Solution
Explanation: Given, [3c+6a−da+d2−3b]=[122−8−4]
∴3c+6=12
a−d=2
a+d=−8
2−3b=−4
From eq. (i), we get c=2
On solving eqs. (ii) and (iii), we get a=−3 and d=−5 from eq. (iv), we get b=2
Now, ab−cd=(−3)2−2(−5)
⇒ab−cd=−6+10=4
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