Explanation for the correct option:
Given: line ‌

x−2

3

=‌

y−3

4

=‌

z−4

5

let ‌

x−2

3

=‌

y−3

4

=‌

z−4

5

=λ
3

^

i

+4

^

j

+5

^

k

=

→

a

will be perpendicular to normal vector of a plane.
Checking option D
So,
=3(2)+4(1)+5(−2)
=6+4−10
=0
Hence, 2x+y−2z=0 is parallel to ‌

x−2

3

=‌

y−3

4

=‌

z−4

5

.