CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper

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Question : 3
Total: 36
If y=Ae5x+Be−5x, then ‌
d2y
dx2
is equal to
Given:
y=Ae5x+Be−5x
∴‌‌
dy
dx
=5Ae5x−5Be−5x

⇒‌
d2y
dx2
=25Ae5x+25Be−5x

⇒‌
d2y
dx2
=25y.
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