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CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper

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Question : 10 of 36
Marks: +1, -0
A die is thrown once. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5 . Then P(AB) is
P(A)=36
P(B)=46
and
P(AB)=16
We know,
P(AB)=P(A)+P(B)P(AB)
=36+4616
=66=1
Option (d) is correct.
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