If y= \sin ^{-1} x+\cos ^{-1} x, find \frac{d y}{d x}.

CBSE Class 12 Math 2019 All India Set 1 Solved Paper

Question : 2 of 29

Marks: +1, -0

y= sin \;^{-1} x+\cos ^{-1} x

, find

\;{d y}/{d x}

Solution:

y= sin \;^{-1} x+\cos ^{-1} x

⇒ \;{d y}/{d x}=\;{d}/{d x} ( sin \;^{-1} x+\cos ^{-1} x)

=\;{d}/{d x} ( sin \;^{-1} x) +\;{d}/{d x} (\cos ^{-1} x)

=\;{1}/{{√{1-x^2}}}-\;{1}/{{√{1-x^2}}}

=0

Therefore,

\;{d y}/{d x}=0

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