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CBSE Class 12 Math 2008 Solved Paper

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Question : 4
Total: 29
Evaluate: |
a+ibc+id
−c+ida−ib
|
Solution:  
|
a+ibc+id
−c+ida−ib
|
= (a + ib) (a – ib) – (c + id) (-c + id)
= (a2–i2b2) – (−c2+i2d2)
= (a2+b2) – (−c2–d2) (∵ i2 = -1)
= a2+b2+c2+d2
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