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CBSE Class 12 Math 2008 Solved Paper

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Question : 8 of 29
Marks: +1, -0
Find a unit vector in the direction of a = 3i^2j^+6k^
Solution:  
The unit vector (a^) in the direction of a is given by a|a|
a^ = 3i^2j^+6k^32+(2)2+62
= 3i^2j^+6k^9+4+36
3i^2j^+6k^49
= 17 [3i^2j^+6k^]
= 37i^27j^+67k^
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