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CBSE Class 12 Chemistry 2023 Outside Delhi Set 1 Solved Paper

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Question : 12 of 35
Marks: +1, -0
For the reaction 3A→2B3 A \rightarrow2 B, rate of reaction +  d[B]dt+\;\frac{d[B]}{dt} is equal to
Solution:     👈: Video Solution
3A→2B3 A \rightarrow2 B
−13d[A]dt=12d[B]dt-\frac{1}{3}\frac{d[A]}{dt}=\frac{1}{2}\frac{d[B]}{dt}
(b) −23d[A]dt-\frac{2}{3}\frac{d[A]}{dt}
⇒+d[B]dt=−23d[A]dt\Rightarrow \frac{+d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}
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