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CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 3

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Question : 2 of 12
Marks: +1, -0
(a) Why on dilution the m\wedge_m of CH3COOH\mathrm{CH}_3\mathrm{COOH} increases very fast, while that of CH3COONa\mathrm{CH}_3\mathrm{COONa} increases gradually?
(b) What happens if external potential applied becomes greater than EE^{\circ} to be in subscript of electrochemical cell?
Solution:  
(i) On dilution m\wedge_m of CH3COOH\mathrm{CH}_3\mathrm{COOH} increases very fast because it is a weak electrolyte and the number of ions also increases due to increase in the degree of dissociation (less than 1). However,in CH3COONa\mathrm{CH}_3\mathrm{COONa} which is a strong electrolyte, the number of ions remains same but the intermolecular forces of attraction decreases and the degree of dissociation is equal to 1 . Thus, m\wedge_m increases gradually in case of CH3COONa\mathrm{CH}_3\mathrm{COONa}.
(ii) If the external potential applied become greater than EE^{\circ} cell of electrochemical cell, then the reaction gets reversed and the electrochemical cell acts as an electrolytic cell and vice-versa.
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