CBSE Class 12 Chemistry 2022 Term 1 Paper

Question : 26

Total: 55

SECTION - B

An unknown gas ' X ' is dissolved in water at 2.5 bar pressure and has mole fraction 0.04 in solution. The mole fraction of ' X ' gas when the pressure of gas is doubled at the same temperature i

0.08
0.04
0.02
0.92

Solution:

Mole fraction of gas X in solution =0.04
Pressure =2.5 bar
Let
p1‌=P0X1
2.5‌=0.04P0 ......(i)
Let pressure be doubled, then p2
5.0=X2P0 ......(ii)
Dividing Eqn ii by eqn I, we get
5.0∕2.5‌=X2∕0.04
2×0.04‌=X2
X2‌=0.08

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