CBSE Class 12 Chemistry 2019 Outside Delhi Set 2 Solved Paper

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Question : 6
Total: 27
SECTION - B

When FeCr2O4 is fused with Na2CO3 in the presence of air it gives a yellow solution of compound (A). Compound (A) on acidification gives compound (B). Compound (B) on reaction with KCl forms an orange coloured compound (C). An acidified solution of compound (C) oxidises Na2SO3 to (D). Identify (A), (B), (C) and (D).
Solution:  
4FeCr2O4+8Na2CO3+‌7O2→
8Na2CrO4+‌8Fe2O3+8CrO2
[A]

2Na2CrO4+2H+→
Na2Cr2O7+2Na++H2O
[B]

Na2Cr2O7+2‌KCl→
K2Cr2O7+2‌NaCl
[C]

K2Cr2O7‌+3Na2SO3+4H2SO4→
3Na2SO4+K2SO4+Cr2(SO4)3+4H2O
[D]

[A] Na2CrO4 : Sodium chromate, [B]Na2Cr2O7. : Sodium dichromate, [C] K2Cr2O7 : Potassium dichromate, [D]Na2SO4 : Sodium sulphate.
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