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CBSE Class 12 Chemistry 2019 Outside Delhi Set 2 Solved Paper

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Question : 6 of 27
Marks: +1, -0
SECTION - B
When FeCr2O4\mathrm{FeCr}_2\mathrm{O}_4 is fused with Na2CO3\mathrm{Na}_2\mathrm{CO}_3 in the presence of air it gives a yellow solution of compound (A). Compound (A) on acidification gives compound (B). Compound (B) on reaction with KCl\mathrm{KCl} forms an orange coloured compound (C). An acidified solution of compound (C) oxidises Na2SO3\mathrm{Na}_2\mathrm{SO}_3 to (D). Identify (A), (B), (C) and (D).
Solution:  
4FeCr2O4+8Na2CO3+7O24\mathrm{FeCr}_2\mathrm{O}_4+8\mathrm{Na}_2\mathrm{CO}_3+7\mathrm{O}_2\rightarrow 8Na2CrO4+8Fe2O3+8CrO2[A]\underset{[A]}{8\mathrm{Na}_2\mathrm{CrO}_4+8\mathrm{Fe}_2\mathrm{O}_3+8\mathrm{CrO}_2}
2Na2CrO4+2H+2\mathrm{Na}_2\mathrm{CrO}_4+2\mathrm{H}^{+}\rightarrow Na2Cr2O7+2Na++H2O[B]\underset{[B]}{\mathrm{Na}_2\mathrm{Cr}_2\mathrm{O}_7+2\mathrm{Na}^{+}+\mathrm{H}_2\mathrm{O}}
Na2Cr2O7+2KCl\mathrm{Na}_2\mathrm{Cr}_2\mathrm{O}_7+2\mathrm{KCl}\rightarrow K2Cr2O7+2NaCl[C]\underset{[C]}{\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7+2\mathrm{NaCl}}
K2Cr2O7+3Na2SO3+4H2SO4\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7+3\mathrm{Na}_2\mathrm{SO}_3+4\mathrm{H}_2\mathrm{SO}_4\rightarrow 3Na2SO4+K2SO4+Cr2(SO4)3+4H2O[D]\underset{[D]}{3\mathrm{Na}_2\mathrm{SO}_4+\mathrm{K}_2\mathrm{SO}_4+\mathrm{Cr}_2(\mathrm{SO}_4)_3+4\mathrm{H}_2\mathrm{O}}
[A] Na2CrO4\mathrm{Na}_2\mathrm{CrO}_4 : Sodium chromate, [B]Na2Cr2O7.[B] \mathrm{Na}_2\mathrm{Cr}_2\mathrm{O}_7. : Sodium dichromate, [C] K2Cr2O7\mathrm{K}_2\mathrm{Cr}_2\mathrm{O}_7 : Potassium dichromate, [D]Na2SO4[D] \mathrm{Na}_2\mathrm{SO}_4 : Sodium sulphate.
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