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CBSE Class 12 Chemistry 2019 Outside Delhi Set 2 Solved Paper

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Question : 2 of 27
Marks: +1, -0
Arrange the following in increasing order of pKbp_{Kb} values:
C6H5CH2NH2, C6H5NHCH3,\mathrm{C}_6\mathrm{H}_5\mathrm{CH}_2\mathrm{NH}_2,\ \mathrm{C}_6\mathrm{H}_5\mathrm{NHCH}_3, C6H5NH2\mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2
Solution:  
C6H5CH2NH2<C6H5NHCH3\mathrm{C}_6\mathrm{H}_5\mathrm{CH}_2\mathrm{NH}_2 < \mathrm{C}_6\mathrm{H}_5\mathrm{NHCH}_3 <C6H5NH2< \mathrm{C}_6\mathrm{H}_5\mathrm{NH}_2
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