For the reaction 2 {\N}_2 {\O}_5( {\g}) \to 4 {\NO}

CBSE Class 12 Chemistry 2018 Solved Paper

Question : 7

Total: 26

For the reaction
2N2O5(g)→4NO2(g)+O2(g)‌, ‌
the rate of formation of NO2(g) is 2.8×10−3M s−1.
Calculate the rate of disappearance of N2O5(g)

Solution:

‌ Rate ‌‌=‌

‌

∆NO2

∆(t)

=‌

‌

∆(N2O5)

∆(t)

‌

(2.8×10−3)‌=−‌

‌

∆(N2O5)

∆(t)

Rate of disappearance of N2O5 (−‌

∆N2O5

∆(t)

)1.4×10−3M∕ s
(Deduct half mark if unit is wrong or not written)

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