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CBSE Class 12 Chemistry 2018 Solved Paper

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Question : 3 of 26
Marks: +1, -0
Write the co-ordination number and oxidation state of Platinum in the complex [Pt(en)2Cl2][\mathrm{Pt}(\mathrm{en})_2\mathrm{Cl}_2].
Solution:  
Co-ordination number == Denticity ×\times Number of ligand =2×2+2×1=6=2\times 2+2\times 1=6
Charge on complex =0=0
Therefore, [x+(0×2)+(−1×2)]=0[x+(0\times 2)+(-1\times 2)]=0
x=+2x=+2
Oxidation state of Pt=+2\mathrm{Pt}=+2
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