Calculate e.m.f. of the following cell at 298 {\K} : 2 ...

CBSE Class 12 Chemistry 2016 Delhi Set 1 Solved Paper

Question : 16

Total: 26

Calculate e.m.f. of the following cell at 298K :
‌2‌Cr( s)+3Fe2+(0.1M)→2Cr3+(0.01M) +3‌Fe( s)
‌‌ Given : ‌E°(Cr3+∣Cr)=−0.74VE∘
(Fe2+∣Fe)=−0.44V3

Solution:

E°‌celi ‌‌=Ec0−Ea0
‌=(−0.44)−(−0.74)V
‌=0.30V
E‌cell ‌‌=E°‌cell ‌−‌

0.059

‌log‌

[Cr3+]2

[Fe2+]3

E‌cell ‌‌=E°‌cell ‌−‌

0.059

‌log‌

[0.01]2

[0.1]3

‌=0.30−(‌

−0.059

)
‌=0.3098V

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