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CBSE Class 12 Chemistry 2013 Solved Paper

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Question : 10
Total: 30
The conductivity of 0.20M solution of KCl at 298K is 0.025Scm−1, Calculate its molar conductivity.
Solution:  
‌ Conductivity ‌‌=0.025Scm−1
‌ molarity, ‌M‌=0.20M
T=298K
Tm=?
molar conductivity =?
Tm=
κ×1000
C
=
0.025×1000Scm−1
0.20‌mol‌cm−3
=
25
0.20
=125 S cm2mol−1
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