Total numbers of outcomes while throwing dice is 1, 2, 3, 4, 5, 6Number greater than 3 are: 4, 6 out of which only one number appears while throwing dice.∴ Probability (number greater than 3) = $\;\frac{\text{favorable outcome}}{\text{Total number of outcomes}}$$=\;\frac{2}{6}$$=\;\frac{1}{3}$