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CBSE Class 10 Standard Math 2025 All Sets Solved Paper

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Question : 18 of 20
Marks: +1, -0
In the adjoining figure, ABCD is a trapezium in which XY||AB||CD. If AX=23ADAX = \frac{2}{3} AD then CY:YB =
Solution:  
Given:-
ABCD is a trapezium where XY∣AB∣CD.X Y \mid A B \mid C D.
AX=23ADA X = \frac{2}{3} A D
We know that,
DXAX=CYYB\frac{DX}{AX} = \frac{CY}{YB}
AD−AXAX=CYYB\frac{AD - AX}{AX} = \frac{CY}{YB}
AD−2AD32AD3=CYYB\frac{AD - \frac{2AD}{3}}{\frac{2AD}{3}} = \frac{CY}{YB} \\
3AD−2AP32AD3=CYYB\frac{\frac{3AD-2AP}{3}}{\frac{2AD}{3}} = \frac{CY}{YB}
AD2AD=CYYB\frac{AD}{2AD} = \frac{CY}{YB}
12=CYYB\frac{1}{2} = \frac{CY}{YB}
CY:YB=1:2CY : YB = 1 : 2
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