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CBSE Class 10 Science 2023 Outside Delhi Set 1

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Question : 34 of 39
Marks: +1, -0
(a) (i) A compound 'A' with a molecular formula of C2H4O2\mathrm{C}_2\mathrm{H}_4\mathrm{O}_2 reacts with a base to give salt and water. Identify ' AA ', state its nature and the name of the functional group it possesses. Write chemical equation for the reaction involved.
(ii) When the above stated compound ' AA ' reacts with another compound ' BB ' having molecular formula C2H6O\mathrm{C}_2\mathrm{H}_6\mathrm{O} in the presence of an acid, a sweet smelling compound is ' C\mathrm{C} ' formed.
(1) Identify ' BB ' and ' CC '
(2) State the role of acid in this reaction.
(3) Write chemical equation for the reaction involved
OR
b) (i) Name the compound formed when ethanol is heated at 443K443\,\mathrm{K} in the presence of conc. H2SO4\mathrm{H}_2\mathrm{SO}_4 and draw its electron dot structure.
State the role of conc. H2SO4\mathrm{H}_2\mathrm{SO}_4 in this reaction.
(ii) What is hydrogenation? Explain it with the help of a chemical equation. State the role of this reaction in industry.
Solution:  
(a) (i) Since,
As we know that, acid reacts with base to give salt and water Compound AA will be acidic in nature with carboxylic acid group.
Chemical equation for acid and base reaction:
Acid+BaseSalt+Water\text{Acid} + \text{Base} \rightarrow \text{Salt} + \text{Water}
HX+MOHMX+HOH\mathrm{HX} + \mathrm{MOH} \rightarrow \mathrm{MX} + \mathrm{HOH}
CH3COOH(aq)+NaOH(aq)CH3COONa(aq)+H2O(l)\mathrm{CH}_3\mathrm{COOH}(a q) + \mathrm{NaOH}(a q) \rightarrow \mathrm{CH}_3\mathrm{COONa}(a q) + \mathrm{H}_2\mathrm{O}(l)
Thus, Compound 'A is CH3COOH\mathrm{CH}_3\mathrm{COOH} it is acidic in nature containing a carboxyl functional group.
(ii) Carboxylic acids can react with alcohols to form esters in a process called Fischer esterification. An acid catalyst is required and the alcohol is also used as the reaction solvent.
(1) Compound B is Ethanol and C is Ethyl acetate.
(2) HCl\mathrm{HCl} act as catalyst.
(3) A sweet-smelling compound formed by reacting acetic acid with ethanol in the presence of hydrochloric acid is ethyl acetate.
CH3COOH+HOC2H5H+CH3COEthyl acetateOC2H5\mathrm{CH_3-} \underset{\mathrm{O}}{\underset{\parallel}{\mathrm{C}}} \mathrm{-OH} + \mathrm{HOC_2H_5} \xrightarrow{\mathrm{H}^+} \mathrm{CH_3-} \underset{\text{Ethyl acetate}}{\underset{\mathrm{O}}{\underset{\parallel}{\mathrm{C}}}} \mathrm{-OC_2H_5}
OR
(b) (i) Ethene is formed when ethanol at 443K443\,\mathrm{K} is heated with excess concentrated sulphuric acid.
The mechanism of acid dehydration of ethanol to yield ethene is:
1. First step is the protonation of oxygen atom of -OH group.
2. Second step is the loss of a molecule of water to form carbonium ion.
3. Last step is deprotonation to form carbon- carbon double bond.
2CH3CH2OHEthanolConc. sulphuric acidΔ2CH2=CH2Ethene+2H2Owater\underset{\text{Ethanol}}{2\mathrm{CH_3CH_2OH}} \xrightarrow[\text{Conc. sulphuric acid}]{\Delta} \underset{\text{Ethene}}{2\mathrm{CH_2=CH_2}} + \underset{\text{water}}{2\mathrm{H_2O}}
Concentrated sulphuric acid can act as a dehydrating agent. Hence, ethanol when heated at 433K433\,\mathrm{K} with excess conc. H2SO4\mathrm{H}_2\mathrm{SO}_4 undergoes dehydration reaction to form ethene.
(ii) Hydrogenation is the process of addition between hydrogen and other compounds in presence of a catalyst.
For example: Alkene can be converted to alkane by using H2\mathrm{H}_2 in presence of metal catalyst such as Pt, Ni\mathrm{Pt},\ \mathrm{Ni} or Pd\mathrm{Pd}
CH2=CH2CH3CH3\mathrm{CH_2=CH_2} \rightarrow \mathrm{CH_3CH_3}
The industrial applications are as follows:
1. To convert alkenes into alkanes.
2. To prepare vegetable ghee from vegetable oils.
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