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CBSE Class 10 Science 2017 Outside Delhi Term II Set 1 Paper

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Question : 3 of 36
Marks: +1, -0
In the following food chain, 100 J100\,\text{J} of energy is available to the lion. How much energy was available to the producer?
Plant →\rightarrow Deer →\rightarrow Lion
Solution:  
10%   of   x=10010\% \;\text{ of }\; x = 100
x=1000  J   in deer   x = 1000 \;\text{J} \;\text{ in deer }\;
10%   of   y=100010\% \;\text{ of }\; y = 1000
y=10,000  J   in Plants   y = 10,000 \;\text{J} \;\text{ in Plants }\;
Then, plants utilise only 1%1\% of energy
1%   of   z=10,0001\% \;\text{ of }\; z = 10,000
z=10,00,000  J   available energy.   z = 10,00,000 \;\text{J} \;\text{ available energy. }\;
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