Given : $u=-30\text{ cm}, f=15\text{ cm}$.We know that, $\;\frac{1}{v}+\;\frac{1}{u}=\;\frac{1}{f}$$\;\frac{1}{v}\;=\;\frac{1}{15}+\;\frac{1}{30}=\;\frac{2+1}{30}=\;\frac{3}{30}$$v\;=10\text{ cm}$ Characteristics of image :(i) Image formed is erect.(ii) Image formed is small in size.(iii) Image formed is virtual.(iv) Image is formed at a distance of $10\text{ cm}$ behind the mirror between focus and pole.