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CBSE Class 10 Math 2023 Delhi Set-2 Solved Paper

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SECTION - B
Section - B consists of Very Short Answer (VSA) type questions of 2 marks each.
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Question : 7 of 11
Marks: +1, -0
(A) Evaluate :   5cot⁡230∘+  1sin⁡260∘−cot⁡245∘+2sin⁡290∘\; \frac{5}{\cot^2 30^{\circ}} + \; \frac{1}{\sin^2 60^{\circ}} - \cot^2 45^{\circ} + 2 \sin^2 90^{\circ}
OR
(B) If θ\theta is an acute angle and sin⁡θ=cos⁡θ\sin \theta = \cos \theta, find the value of tan⁡2θ+cot⁡2θ−2\tan^2 \theta + \cot^2 \theta - 2
Solution:     👈: Video Solution
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