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CBSE Class 10 Math 2023 Delhi Set-1 Solved Paper

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Question : 29 of 38
Marks: +1, -0
(A) Prove that sin⁡A−2sin⁡3A2cos⁡3A−cos⁡A=tan⁡A\frac{\sin A - 2 \sin^3 A}{2 \cos^3 A - \cos A} = \tan A
OR
(B) Prove that sec⁡A(1−sin⁡A)(sec⁡A+tan⁡A)=1\sec A (1 - \sin A)(\sec A + \tan A) = 1.
Solution:     👈: Video Solution
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