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CBSE Class 10 Math 2023 Delhi Set-1 Solved Paper

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Question : 25 of 38
Marks: +1, -0
(A) Evaluate   5cos⁡260∘+4sec⁡230∘−tan⁡245∘sin⁡230∘+cos⁡230∘\;\frac{5\cos^2 60^{\circ}+4\sec^2 30^{\circ}-\tan^2 45^{\circ}}{\sin^2 30^{\circ}+\cos^2 30^{\circ}}
OR
(B) If AA and BB are acute angles such that sin⁡(A−B)=0\sin (A-B)=0 and 2cos⁡(A+B)−1=02\cos (A+B)-1=0, then find angles AA and BB.
Solution:     👈: Video Solution
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