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CBSE Class 10 Basic Math 2026 All Sets Solved Paper

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Question : 1 of 20
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Probability of getting an irrational number at random from the numbers 3, 4, 39, 38, 5, 0, 4  32\sqrt{3},\, \sqrt{4},\, 3\sqrt{9},\, 3\sqrt{8},\, \sqrt{5},\, 0,\, 4^{\;\frac{3}{2}} is :
Solution:  
Given numbers: 3, 4, 39, 38, 5, 0, 4  32\sqrt{3},\, \sqrt{4},\, 3\sqrt{9},\, 3\sqrt{8},\, \sqrt{5},\, 0,\, 4^{\;\frac{3}{2}}
Total number of elements (n(S)) = 7.
Number of irrational numbers = 3(3,38,5)3(\sqrt{3}, 3\sqrt{8}, \sqrt{5})
Number of favorable outcomes (n(E)) = 3.
P(Irrational) =   n(E)n(S)=  37\;\frac{n(E)}{n(S)} = \;\frac{3}{7}
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