Concept:The volume of a cube is directly proportional to the cube of its side length.Explanation:Let's consider a cube with an initial side length. We can represent this initial side length using a variable.Let the initial side length of the cube be $s$.The initial volume of the cube, $V_{initial}$, is given by the formula: $V_{initial} = s^3$.Now, the problem states that each edge of the cube is doubled. So, the new side length becomes $2s$.The new volume of the cube, $V_{new}$, will be: $V_{new} = (2s)^3$.Calculating this, we get: $V_{new} = 2^3 \times s^3 = 8s^3$.To find out how many times the volume has increased, we compare the new volume to the initial volume:Ratio of new volume to initial volume = $\frac{V_{new}}{V_{initial}} = \frac{8s^3}{s^3}$.Simplifying this ratio, we get $\frac{8s^3}{s^3} = 8$.This means the new volume is 8 times the initial volume.Answer:8 times