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TGTET Paper 1 Exam 23 Jul 2017 Paper

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Question : 105 of 150
Marks: +1, -0
The length of a Rectangle is 3 cm more than its breadth. If its perimeter i is 30 cm, then its length is (in cm) ______
Solution:  
Concept:
Understanding the relationship between the perimeter, length, and breadth of a rectangle.
Explanation:
Let's denote the breadth of the rectangle as bb cm and the length as ll cm.
We are given two pieces of information:
1. The length is 3 cm more than its breadth: l=b+3l = b + 3. This can also be written as l−b=3l - b = 3.
2. The perimeter of the rectangle is 30 cm.
The formula for the perimeter of a rectangle is P=2×(l+b)P = 2 \times (l + b).
Substituting the given perimeter, we get 30=2×(l+b)30 = 2 \times (l + b).
Dividing both sides by 2, we find l+b=15l + b = 15.
Now we have a system of two linear equations:
Equation (1): l+b=15l + b = 15
Equation (2): l−b=3l - b = 3
To find the length (ll), we can add Equation (1) and Equation (2):
(l+b)+(l−b)=15+3(l + b) + (l - b) = 15 + 3
2l=182l = 18
Divide by 2 to get the length: l=182=9l = \frac{18}{2} = 9 cm.
We can also find the breadth by substituting l=9l=9 into Equation (1): 9+b=159 + b = 15, which gives b=15−9=6b = 15 - 9 = 6 cm.
The question asks for the length of the rectangle.
Answer:
9 cm
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