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MHT CET 2020 Physics Solved Paper
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© examsnet.com
Question : 2
Total: 50
If three equal masses
m
are placed at the three vertices of an equilateral triangle of side
1
∕
m
then what force acts on a particle of mass
2
m
placed at the centroid?
G
m
2
2
G
m
2
Zero
−
G
m
2
Validate
Solution:
F
G
A
=
G
m
(
2
m
)
1
∧
j
F
G
B
=
G
m
(
2
m
)
1
(
−
∧
i
cos
30
∘
−
∧
j
sin
30
∘
)
F
G
C
=
G
m
(
2
m
)
1
(
∧
i
cos
30
∘
−
∧
j
sin
30
∘
)
Resultant force on
(
2
m
)
is
F
R
=
F
G
A
+
F
G
B
+
F
G
C
=
2
G
m
2
∧
j
+
2
G
m
2
∧
i
(
−
cos
30
∘
+
cos
30
∘
)
+
2
G
m
2
∧
j
(
−
sin
30
∘
−
sin
30
∘
)
=
2
G
m
2
∧
j
.2
G
m
2
∧
j
(
−
2
×
1
2
)
=
2
G
m
2
∧
j
−
2
G
m
2
∧
j
=
0
© examsnet.com
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