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AIPMT 2003 Physics and Chemistry Paper
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© examsnet.com
Question : 3
Total: 100
A thin circular ring
M
and radius '
r
' is rotating about its axis with a constant angular velocity
ω
. Four objects each of mass
m
, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be -
M
ω
4
m
M
ω
M
+
4
m
(
M
+
4
m
)
ω
M
(
M
+
4
m
)
ω
M
+
4
m
Validate
Solution:
Use law of conservation of angular momentum.
M
r
2
ω
=
(
M
r
2
+
4
m
r
2
)
ω
′
⇒
ω
′
=
M
ω
M
+
4
m
© examsnet.com
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