When a natural number x is divided by ‘5’, the remainder is 2 ∴ x=5P+2 ... (i) When a natural number y is divided by ‘5’ the remainder is 4 ∴ ;y=5Q+4 ... (ii) When x + y is divided by ‘5’, the remainder is z Adding Eq. (i) and (ii), we get x+y=5(P+Q)+6 Now when x + y is divided by ‘5’ remainder will be 1 ∴ z=1 Hence the value of