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JEE Mains 2020 Model Paper 2 - New Pattern
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© examsnet.com
Question : 2
Total: 75
If x + cos θ = sec θ , y +
c
o
s
8
θ =
s
e
c
8
θ then
(
x
2
+
4
y
+
4
)
(
d
y
d
x
)
2
=
8
16
64
49
Validate
Solution:
d
y
d
x
=
8
s
e
c
8
q
t
a
n
q
+
8
c
o
s
7
q
s
i
n
q
s
e
c
q
t
a
n
q
+
s
i
n
q
=
8
t
a
n
q
(
s
e
c
8
q
+
c
o
s
8
q
)
t
a
n
q
(
s
e
c
q
+
c
o
s
q
)
(
d
y
d
x
)
2
=
64
(
s
e
c
8
θ
+
c
o
s
8
θ
)
(
s
e
c
θ
+
c
o
s
θ
)
2
=
64
[
(
s
e
c
8
θ
−
c
o
s
8
θ
)
2
+
4
]
[
(
s
e
c
θ
−
c
o
s
θ
)
2
+
4
]
=
64
(
y
2
+
4
)
(
x
2
+
4
)
(
x
2
+
4
y
+
4
)
(
d
y
d
x
)
2
= 64
© examsnet.com
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