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AIEEE 2012 Solved Paper
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© examsnet.com
Question : 41
Total: 89
A wooden wheel of radius
R
is made of two semicircular part (see figure). The two parts are held together by a ring made of a metal strip of cross sectional area
S
and length
L
.
L
is slightly less than
2
π
R
. To fit the ring on the wheel, it is heated so that its temperature rises by
∆
T
and it just steps over the wheel. As it cools down to surrounding temperature, it process the semicircular parts together. If the coefficient of linear expansion of the metal is
α
, and its Young's modulus is
Y
, the force that one part of the wheel applies on the other part is:
2
π
S
Y
α
∆
T
S
Y
α
∆
T
π
S
Y
α
∆
T
2
S
Y
α
∆
T
Validate
Solution:
γ
=
F
∕
S
∆
L
∕
L
⇒
∆
L
=
F
L
S
Y
∴
L
α
∆
T
=
F
L
S
Y
[
as
∆
L
=
L
α
∆
T
]
∴
F
=
S
Y
α
∆
T
∴
The ring is pressing the wheel from both sides,
∴
F
n
e
t
=
2
F
=
2
Y
S
α
∆
T
© examsnet.com
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