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Question : 1
Total: 27
Solution:
Here, M = 2.50 kg, T = 200 N, length of the string, l = 20 m
Therefore, mass per unit length of the string,
µ=
2.5
20
=0.125kgm1

Now, v=
T
µ
=
200
0.125
=40ms1

Therefore, time taken by the transverse jerk to reach the other end,
t=
l
v
=
20
40
=0.5s
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