Test Index

## Waves

Question : 1

Total: 27

**Solution:**

Here, M = 2.50 kg, T = 200 N, length of the string, l = 20 m

Therefore, mass per unit length of the string,

µ =

= 0.125 kg m − 1

Now,v = √

= √

= 40 m s − 1

Therefore, time taken by the transverse jerk to reach the other end,

t =

=

= 0.5 s

Therefore, mass per unit length of the string,

Now,

Therefore, time taken by the transverse jerk to reach the other end,

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