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Kinetic Theory

Question : 1
Total: 14
Solution:
Here, the diameter of an oxygen molecule, d=3Å=3×1010m
The radius of an oxygen molecule
r=
d
2
=
3×1010
2
m

Molecular volume of one mole of oxygen, V
= Volume of one molecule of oxygen × Avogadro number(N)
=
4
3
π
r3
×N

V=
4
3
×3.14
×(
3×1010
2
)
3
×6.023
×1023
=8.52×106m3
Actual volume occupied by one mole of oxygen gas at S.T.P.V=22,400cm3
=22,400×106m3
∴ Fraction of molecular volume of the actual volume occupied by
O2=
V
V

=
8.52×106
22,400×106

=3.8×1044×104
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